MATLAB: Vectors, Sequential Elements and rand -

MATLAB: Vectors, Sequential Elements and rand -

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given vector of n elements a_{n},n =1,2,...,n, simple moving average of m sequential elements of vector defined as

mu(j) = mu(j-1) + (a(m+j-1)-a(j-1))/m j = 2,3,...,(n-m+1)

where

mu(1) = sum(a(k))/m k = 1,2,...,m

write script computes these moving averages when a given a=5*(1+rand(n,1)), rand generates uniformly distributed random numbers. assume n=100 , m=6. plot results using plot(j,mu(j)) j=1,2,...,n-m+1.

my current code below, i'm not sure go here or if it's right.

close clear clc n = 100; m = 6; = 5*(1+rand(n,1)); mu = zeros(n-m+1,1); mu(1) = sum(a(1:m)); j=2 mu(j) = mu(j-1) + (a-a)/m end plot(1:n-m+1,mu)

i'll step through modifications.

firstly, mu(1) not defined. equation given incorrect, should be:

mu(1) = sum(a(1:m))/m;

then for loop has go j=2 j=n-m+1

for j=2:n-m+1

and @ each step, mu(j) given formula, same given in question

mu(j) = mu(j-1) + (a(m+j-1)-a(j-1))/m

and that's need change!

matlab vector moving-average