Edit: I do not think how the second question gives me an answer. I already have a clear artist (e []), who is not the author of the second question. I also tried something like seq1 = (integer []) iw.result (); But that does not work either.
I have the following code:
Public class is something comparative & lt; E & gt; & Gt; {E] [] Sack; Some public () {seq = (e []) new object [100]; } Public E [] results () {Return sequence; } Public static zero main (string [] args) {some & lt; Integer & gt; Iw = new something & lt; Integer & gt; (); Integer [] sAC1 = new integer [100]; Seq1 = iw.result (); }} I get a misunderstanding in this way: [Object can not be inserted in [Comparative
, so I change some-maker to:
seq = (e []) new comparative [100]; Now I get a misunderstanding in this way: [Comparative can not be inserted into [integer]
Is there any way to work above code? I know I'm better off working with collections, but I'm just curious what's wrong with my code.
Here are some problems.
First of all, this is not an unlimited general parameter; enclosed comparative
During the extinction of type, your class has been declared as:
public class something & lt; E comparative & lt; E & gt; & Gt; {E] [] Sack; } ... is bound to e comparative .
public squares some {comparative [] Seq; } This therefore your casting is not working, because object is not a comparable . You want to use the new comparative instead.
public class something & lt; E extractable comparative & lt; E & gt; & Gt; {E] [] Sack; Some public () {seq = (e []) new comparative [100]; }} Now, Java and should break on the previous two statements.
integer [] seq1 = new integer [100]; Seq1 = iw.result (); is bound to iw.result () comparative [] , not integer [] . A comparative [] can never become a integer [] .
You can do this instead to leave ClassCastException :
comparative [] seq1 = new integer [100]; This will work since a integer is comparative . This is due to the fact that arrays are co-sensation (which is a subtype of a integer [a] a comparable [] ).
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