How to create a function (Iteration/Recursion) to run over a dictionary of tuples in Python? -

How to create a function (Iteration/Recursion) to run over a dictionary of tuples in Python? -

i have python dictionary of lists one:

d = {'a': [(4, 4, 3), [1, 2, 3, 4, 5]], 'b': [(2, 1, 2), [5, 4, 3, 2, 1]], 'c': [(4, 1, 1), [2, 4, 1, 2, 4]]}

i need create formula accesses elements of dictionary and, every value [t, l]:

calculates mean of t (let's phone call m); takes random sample s, replacement , of length len(t), l; compares m mean of s - true if m greater mean of s, false otherwise; repeats process 10,000 times returns percentage of times m greater mean of s.

the output should like:

in [16]: test(d) out[16]: {'a': 0.5, 'b': 0.9, 'c': 0.4}

i think i'm not far answer, have tried:

def test(dict): def mean_diff(dict): k, (v0, v1) in dict.iteritems(): m = np.mean(v0) > (np.mean(npr.choice(v1, size=(1, len(v0)), replace=true))) homecoming ({k: m}) k, (v0, v1) in dict.iteritems(): bootstrap = np.array([means_diff(dict) _ in range(10000)]) rank = float(np.sum(bootstrap))/10000 homecoming ({k: rank})

however, got:

runtimeerror: maximum recursion depth exceeded while calling python object

i'd utilize list comprehension selects random value , compares mean. produce list of true/false. if take mean of that, averaging list of 1's , 0's, give aggregate probability.

import numpy np d = {'a': [(4, 4, 3), [1, 2, 3, 4, 5]], 'b': [(2, 1, 2), [5, 4, 3, 2, 1]], 'c': [(4, 1, 1), [2, 4, 1, 2, 4]]} def makeranks(d): rankdict = {} key in d: tup = d[key][0] mean = np.mean(tup) l = d[key][1] rank = np.mean([mean > np.mean(np.random.choice(l,len(tup))) _ in range(10000)]) rankdict[key] = rank homecoming rankdict

testing

>>> makeranks(d) {'c': 0.15529999999999999, 'a': 0.72130000000000005, 'b': 0.031899999999999998}

python function recursion dictionary iteration