python - checking a string to see if it is in alphabetical order -

python - checking a string to see if it is in alphabetical order -

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how check if characters in string alphabetically ordered 5 answers

i learning python. current self taught assignment write programme takes string , checks weather or not the letters in string in alphabetical order. if not, programme homecoming number of instances letters out of order. inquire help of stackoverflow, code me looks maintain getting error, of included below.

the code

def inversions (string): res = 0 in string: if string[i+1] < string[i]: res += 1 print( res)

my errors

traceback (most recent phone call last): file "<pyshell#1>", line 1, in <module> inversions ('ghutinhjdbessadfg') file "c:\users\christopher\downloads\pratice.py", line 63, in inversions if string[i+1] < string[i]: typeerror: can't convert 'int' object str implicitly

i kinda error saying, unsure of it.

thank much

it ambiguous mean how many out of order - illustration string

zabcdef

has of letters out of order. mean, or want number of operations required re-order string?

to check see if strings alphabetical, seek reply question:

checking if string in alphabetical order in python

def isinalphabeticalorder(word): in range(len(word) - 1): if word[i] > word[i + 1]: homecoming false homecoming true

your problem because using strings list indices.

taking code example, have modified above give

def number_out_of_place(word): out_of_place = 0 in range(len(word) - 1): if word[i] > word[i + 1]: out_of_place += 1 homecoming out_of_place

python