bash - Shell script print line number when it errors out -

I am looking for a way to print line numbers inside the line script during errors of errors.

I came to the '-x' option, which prints the line while running the shell script, but this is not what I need. Maybe I can $ LINENO before each exit code? Is there a cleaner way to do this?

I just wanted the line number so that I could open the shell script and go straight to the place where the interpreter realized the error. Using

  PS4 = ': $ LINENO +'  

will add line numbers to the output of set -x .

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If you want to print on only errors, then there is some risk to it being running in insects among recent interpreters, however, You can try:

  error () {local parent_lineno = "$ 1" local message = "$ 2" local code = "$ {3: -1}" if [[- N "$ message"]]; Then "$ {parent_lineno}: $ {parent_lineno} on line $ {parent_lineno}: resonates error; status goes with $ $ {code}" "second echo" error; $ {parent_linen}; $$ {code} "ex exit" $ {Code} "} 'error $ {LINENO}' ERR  

Again, this will not work On the construction of some bass, which does not always set correctly inside the lineno trap.

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Another approach (which only Will work on recent shells; 4.1 attributes) Each code has to use the PS4 to use the exit status and line number for a dedicated file descriptor, and only use it To print the line, use tail before shell removal FD:

  exec {BASH_XTRACEFD}> gt; & gt; (tail-N1) # Set set-x output tail- n 1 ps4 = 'line $ LINENO; pre-order exit status $? +' Set-x