html - string search returns none or [] -

html - string search returns none or [] -

i have several urls want open specific place , search specific name i'm getting none returned or [].

i have searched cannot see reply pertinent code.

from bs4 import beautifulsoup urllib import request webpage = request.urlopen("http://www.dsfire.gov.uk/news/newsdesk/incidentspast7days.cfm?sitecategoryid=3&t1id=26&t2id=35") soup = beautifulsoup(webpage) incidents = soup.find(id="collapsiblepanel1") links = [] line in incidents.find_all('a'): links.append("http://www.dsfire.gov.uk/news/newsdesk/"+line.get('href')) n = 0 e = len(links) while n < e: webpage = request.urlopen(links[n]) soup = beautifulsoup(webpage) station = soup.find(id="incidentdetailcontainer") #search string print(soup.body.findall(text='ashburton')) n=n+1

i know in lastly link found on page.

thanks in advance ideas or comments

if ouput "[]" only, means output array. have set index => variable[index].

try one

print(soup.body.findall(text='ashburton')[0])

...where storing variable first easier:

search = soup.body.findall(text='ashburton') print(search[0])

this bring first found item.

for printing found items go

search = soup.body.findall(text='ashburton') foreach(entry in search) print(entry)

notice more pseude-code instead of working example. dont know beautifulsoap.

html string list search beautifulsoup