ios - How to call selector from switch only when change to state ON in Swift? -

ios - How to call selector from switch only when change to state ON in Swift? -

i need phone call function selector when alter switch, when set switch on state:

cell.switchmy.addtarget(self, action: "openview", forcontrolevents: uicontrolevents.valuechanged) func openview(){ var cell:customcell = self.tableview.dequeuereusablecellwithidentifier("cell5") customcell if(cell.switchmy.on == true){ println("on") self.performseguewithidentifier("segueunl", sender: self) } }

if utilize code, phone call function, 'm controlling if switch state on... how can correctly?

this (nearly) right way this. can't have method called when switch state on. don't need retrieve cell openview method. sender passed caller:

cell.switchmy.addtarget(self, action: "openview:", forcontrolevents: uicontrolevents.valuechanged) func openview(sender: uiswitch){ if(sender.on) { println("on") self.performseguewithidentifier("segueunl", sender: self) } }

be careful: selector used in addtarget needs changed openview openview:

ios xcode swift