xml - How to find element that matches xslt attribute value in for-each loop -

xml - How to find element that matches xslt attribute value in for-each loop -

suppose have next xml:

<data> <foos> <foo id="1" checked="yes" /> <foo id="2" /> <foo id="3" /> <foo id="4" checked="yes" /> </foos> <bars> <bar for="1" name="blub" /> <bar for="2" name="bla" /> <bar for="3" name="baz" /> <bar for="4" name="plim" /> </bars> </data>

now want print name attributes of element bar point element foo has attribute checked. illustration above, xslt output blub , plim.

here have tried far check whether can print id attribute of foo element each bar belongs to:

<xsl:template match="/"> <xsl:for-each select="//bars/bar"> <xsl:value-of select="../../foos/foo[@id=./@for]/@id" /> </xsl:for-each> </xsl:template>

but no avail. think problem is, check foo[@id=./@for] select both @id , @for foo element. how can want @for attribute current element in loop @id other current element?

how can want @for attribute current element in loop @id other current element?

use the current() function:

<xsl:value-of select="../../foos/foo[@id=current()/@for]/@id" />

inside square brackets, . node predicate testing, whereas current() node current target of for-each.

xml xslt